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1331300423 is a prime number
BaseRepresentation
bin100111101011010…
…0000100001000111
310102210002001212002
41033112200201013
510211303103143
6340034215515
744663603225
oct11726404107
93383061762
101331300423
11623536792
12311a2459b
13182a76b3b
14c8b4bb15
157bd245b8
hex4f5a0847

1331300423 has 2 divisors, whose sum is σ = 1331300424. Its totient is φ = 1331300422.

The previous prime is 1331300407. The next prime is 1331300429. The reversal of 1331300423 is 3240031331.

It is a strong prime.

It is an emirp because it is prime and its reverse (3240031331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1331300423 - 24 = 1331300407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331300395 and 1331300404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331300429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665650211 + 665650212.

It is an arithmetic number, because the mean of its divisors is an integer number (665650212).

Almost surely, 21331300423 is an apocalyptic number.

1331300423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331300423 is an equidigital number, since it uses as much as digits as its factorization.

1331300423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 20.

The square root of 1331300423 is about 36486.9897771795. The cubic root of 1331300423 is about 1100.0827549311.

Adding to 1331300423 its reverse (3240031331), we get a palindrome (4571331754).

The spelling of 1331300423 in words is "one billion, three hundred thirty-one million, three hundred thousand, four hundred twenty-three".