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133130113100 = 22521331301131
BaseRepresentation
bin111101111111100101…
…1000101000001001100
3110201122001210110120122
41323333023011001030
54140122302104400
6141054212204112
712422042201345
oct1737713050114
9421561713518
10133130113100
1151507529466
1221975009638
13c72851416a
14662d0a10cc
1536e2a59685
hex1eff2c504c

133130113100 has 18 divisors (see below), whose sum is σ = 288892345644. Its totient is φ = 53252045200.

The previous prime is 133130113097. The next prime is 133130113117. The reversal of 133130113100 is 1311031331.

It is a super-2 number, since 2×1331301131002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 665650466 + ... + 665650665.

It is an arithmetic number, because the mean of its divisors is an integer number (16049574758).

Almost surely, 2133130113100 is an apocalyptic number.

133130113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133130113100 is an abundant number, since it is smaller than the sum of its proper divisors (155762232544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133130113100 is a wasteful number, since it uses less digits than its factorization.

133130113100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1331301145 (or 1331301138 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 133130113100 its reverse (1311031331), we get a palindrome (134441144431).

The spelling of 133130113100 in words is "one hundred thirty-three billion, one hundred thirty million, one hundred thirteen thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1331301131 2662602262 5325204524 6656505655 13313011310 26626022620 33282528275 66565056550 133130113100