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133130254549 is a prime number
BaseRepresentation
bin111101111111100101…
…1100111100011010101
3110201122002001122121111
41323333023213203111
54140122321121144
6141054215215021
712422043330625
oct1737713474325
9421562048544
10133130254549
1151507615766
1221975077471
13c728563666
14662d0da885
1536e2a86534
hex1eff2e78d5

133130254549 has 2 divisors, whose sum is σ = 133130254550. Its totient is φ = 133130254548.

The previous prime is 133130254513. The next prime is 133130254553. The reversal of 133130254549 is 945452031331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101925032049 + 31205222500 = 319257^2 + 176650^2 .

It is an emirp because it is prime and its reverse (945452031331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133130254549 - 211 = 133130252501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133130254559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66565127274 + 66565127275.

It is an arithmetic number, because the mean of its divisors is an integer number (66565127275).

Almost surely, 2133130254549 is an apocalyptic number.

It is an amenable number.

133130254549 is a deficient number, since it is larger than the sum of its proper divisors (1).

133130254549 is an equidigital number, since it uses as much as digits as its factorization.

133130254549 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 40.

The spelling of 133130254549 in words is "one hundred thirty-three billion, one hundred thirty million, two hundred fifty-four thousand, five hundred forty-nine".