Base | Representation |
---|---|
bin | 11110010001010011111010… |
… | …000001011111000100100110 |
3 | 122110101012101100202220000100 |
4 | 132101103322001133010212 |
5 | 114422204242224001410 |
6 | 1151051312035324530 |
7 | 40020253212121122 |
oct | 3621237201370446 |
9 | 573335340686010 |
10 | 133131001000230 |
11 | 394685a438a352 |
12 | 12b2181aa50746 |
13 | 593927948712c |
14 | 24c380948c582 |
15 | 105d09997d8c0 |
hex | 7914fa05f126 |
133131001000230 has 192 divisors, whose sum is σ = 352721991398400. Its totient is φ = 34831846129920.
The previous prime is 133131001000223. The next prime is 133131001000271. The reversal of 133131001000230 is 32000100131331.
It is a happy number.
133131001000230 is a `hidden beast` number, since 1 + 331 + 3 + 1 + 0 + 0 + 100 + 0 + 230 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1128561991 + ... + 1128679949.
It is an arithmetic number, because the mean of its divisors is an integer number (1837093705200).
Almost surely, 2133131001000230 is an apocalyptic number.
133131001000230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 133131001000230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176360995699200).
133131001000230 is an abundant number, since it is smaller than the sum of its proper divisors (219590990398170).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133131001000230 is a wasteful number, since it uses less digits than its factorization.
133131001000230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118899 (or 118896 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 133131001000230 its reverse (32000100131331), we get a palindrome (165131101131561).
The spelling of 133131001000230 in words is "one hundred thirty-three trillion, one hundred thirty-one billion, one million, two hundred thirty", and thus it is an aban number.
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