Base | Representation |
---|---|
bin | 10011010111111000111… |
… | …110110100110000100001 |
3 | 11201021101010102122202112 |
4 | 103113320332310300201 |
5 | 133303021430104212 |
6 | 2455333445125105 |
7 | 165120255150266 |
oct | 23277076646041 |
9 | 4637333378675 |
10 | 1331322113057 |
11 | 473679697342 |
12 | 1960290b9795 |
13 | 9870a36a651 |
14 | 4861742d26d |
15 | 2496db5b422 |
hex | 135f8fb4c21 |
1331322113057 has 2 divisors, whose sum is σ = 1331322113058. Its totient is φ = 1331322113056.
The previous prime is 1331322112969. The next prime is 1331322113071. The reversal of 1331322113057 is 7503112231331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 789403818256 + 541918294801 = 888484^2 + 736151^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331322113057 - 238 = 1056444206113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331322173057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665661056528 + 665661056529.
It is an arithmetic number, because the mean of its divisors is an integer number (665661056529).
Almost surely, 21331322113057 is an apocalyptic number.
It is an amenable number.
1331322113057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331322113057 is an equidigital number, since it uses as much as digits as its factorization.
1331322113057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 32.
Adding to 1331322113057 its reverse (7503112231331), we get a palindrome (8834434344388).
The spelling of 1331322113057 in words is "one trillion, three hundred thirty-one billion, three hundred twenty-two million, one hundred thirteen thousand, fifty-seven".
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