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133134320526113 is a prime number
BaseRepresentation
bin11110010001010110111111…
…111000011110001100100001
3122110101111221201001021110102
4132101112333320132030201
5114422233042023313423
61151053021300312145
740020431400456134
oct3621267770361441
9573344851037412
10133134320526113
1139469a48150275
1212b223a66a2655
135939688114b2a
1424c3a422ac21b
15105d1e10dbc28
hex7915bfe1e321

133134320526113 has 2 divisors, whose sum is σ = 133134320526114. Its totient is φ = 133134320526112.

The previous prime is 133134320526107. The next prime is 133134320526169. The reversal of 133134320526113 is 311625023431331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86892375705664 + 46241944820449 = 9321608^2 + 6800143^2 .

It is a cyclic number.

It is not a de Polignac number, because 133134320526113 - 230 = 133133246784289 is a prime.

It is a super-2 number, since 2×1331343205261132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133134320526173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66567160263056 + 66567160263057.

It is an arithmetic number, because the mean of its divisors is an integer number (66567160263057).

Almost surely, 2133134320526113 is an apocalyptic number.

It is an amenable number.

133134320526113 is a deficient number, since it is larger than the sum of its proper divisors (1).

133134320526113 is an equidigital number, since it uses as much as digits as its factorization.

133134320526113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 38.

Adding to 133134320526113 its reverse (311625023431331), we get a palindrome (444759343957444).

The spelling of 133134320526113 in words is "one hundred thirty-three trillion, one hundred thirty-four billion, three hundred twenty million, five hundred twenty-six thousand, one hundred thirteen".