Base | Representation |
---|---|
bin | 1100000110111100101010… |
… | …0000011011101100110000 |
3 | 1202010202110210020001001012 |
4 | 3001233022200123230300 |
5 | 3221112022243300000 |
6 | 44152045450130052 |
7 | 2542603653405302 |
oct | 301571240335460 |
9 | 52122423201035 |
10 | 13313501150000 |
11 | 42732513538a7 |
12 | 15b02b4720928 |
13 | 7575c495437c |
14 | 34053c2a7972 |
15 | 1814ac28b735 |
hex | c1bca81bb30 |
13313501150000 has 120 divisors (see below), whose sum is σ = 32314405839408. Its totient is φ = 5313370400000.
The previous prime is 13313501149999. The next prime is 13313501150029. The reversal of 13313501150000 is 5110531331.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 21849470 + ... + 22450530.
Almost surely, 213313501150000 is an apocalyptic number.
13313501150000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13313501150000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16157202919704).
13313501150000 is an abundant number, since it is smaller than the sum of its proper divisors (19000904689408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13313501150000 is an frugal number, since it uses more digits than its factorization.
13313501150000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 601537 (or 601511 counting only the distinct ones).
The product of its (nonzero) digits is 675, while the sum is 23.
Adding to 13313501150000 its reverse (5110531331), we get a palindrome (13318611681331).
The spelling of 13313501150000 in words is "thirteen trillion, three hundred thirteen billion, five hundred one million, one hundred fifty thousand".
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