133135204055753 has 2 divisors, whose sum is σ = 133135204055754. Its totient is φ = 133135204055752.

The previous prime is 133135204055663. The next prime is 133135204055771. The reversal of 133135204055753 is 357550402531331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118786282783744 + 14348921272009 = 10898912^2 + 3787997^2 .

It is a cyclic number.

It is not a de Polignac number, because 133135204055753 - 2¹² = 133135204051657 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133135204055698 and 133135204055707.

It is not a weakly prime, because it can be changed into another prime (133135104055753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66567602027876 + 66567602027877.

It is an arithmetic number, because the mean of its divisors is an integer number (66567602027877).

Almost surely, 2^{133135204055753} is an apocalyptic number.

It is an amenable number.

133135204055753 is a deficient number, since it is larger than the sum of its proper divisors (1).

133135204055753 is an equidigital number, since it uses as much as digits as its factorization.

133135204055753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2835000, while the sum is 47.

The spelling of 133135204055753 in words is "one hundred thirty-three trillion, one hundred thirty-five billion, two hundred four million, fifty-five thousand, seven hundred fifty-three".