Base | Representation |
---|---|
bin | 10011010111111010110… |
… | …110010111011010100111 |
3 | 11201021110022101202011122 |
4 | 103113322312113122213 |
5 | 133303102440401101 |
6 | 2455340524524155 |
7 | 165121115415134 |
oct | 23277266273247 |
9 | 4637408352148 |
10 | 1331353450151 |
11 | 47369535036a |
12 | 1960376b065b |
13 | 987139c00ca |
14 | 4861b66958b |
15 | 2497179b51b |
hex | 135fad976a7 |
1331353450151 has 2 divisors, whose sum is σ = 1331353450152. Its totient is φ = 1331353450150.
The previous prime is 1331353450109. The next prime is 1331353450157. The reversal of 1331353450151 is 1510543531331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1331353450151 - 230 = 1330279708327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331353450157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665676725075 + 665676725076.
It is an arithmetic number, because the mean of its divisors is an integer number (665676725076).
Almost surely, 21331353450151 is an apocalyptic number.
1331353450151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331353450151 is an equidigital number, since it uses as much as digits as its factorization.
1331353450151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 1331353450151 its reverse (1510543531331), we get a palindrome (2841896981482).
The spelling of 1331353450151 in words is "one trillion, three hundred thirty-one billion, three hundred fifty-three million, four hundred fifty thousand, one hundred fifty-one".
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