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13314040098473 is a prime number
BaseRepresentation
bin1100000110111110101010…
…1000010110111010101001
31202010210212100100110100202
43001233222220112322221
53221114123231122343
644152215141441545
72542623216400532
oct301575250267251
952123770313322
1013314040098473
1142734a85a2864
1215b04251102b5
1375767c4c54aa
1434058dabb689
151814de749db8
hexc1beaa16ea9

13314040098473 has 2 divisors, whose sum is σ = 13314040098474. Its totient is φ = 13314040098472.

The previous prime is 13314040098451. The next prime is 13314040098479. The reversal of 13314040098473 is 37489004041331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9343732789504 + 3970307308969 = 3056752^2 + 1992563^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13314040098473 is a prime.

It is not a weakly prime, because it can be changed into another prime (13314040098479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657020049236 + 6657020049237.

It is an arithmetic number, because the mean of its divisors is an integer number (6657020049237).

Almost surely, 213314040098473 is an apocalyptic number.

It is an amenable number.

13314040098473 is a deficient number, since it is larger than the sum of its proper divisors (1).

13314040098473 is an equidigital number, since it uses as much as digits as its factorization.

13314040098473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 870912, while the sum is 47.

The spelling of 13314040098473 in words is "thirteen trillion, three hundred fourteen billion, forty million, ninety-eight thousand, four hundred seventy-three".