Base | Representation |
---|---|
bin | 111101111111111111… |
… | …0001110111100001001 |
3 | 110201200000000202121121 |
4 | 1323333332032330021 |
5 | 4140134220214311 |
6 | 141055411435241 |
7 | 12422264162452 |
oct | 1737776167411 |
9 | 421600022547 |
10 | 133143523081 |
11 | 51514058598 |
12 | 219795b5b21 |
13 | c72b22ab6a |
14 | 6630b92129 |
15 | 36e3d07b71 |
hex | 1efff8ef09 |
133143523081 has 2 divisors, whose sum is σ = 133143523082. Its totient is φ = 133143523080.
The previous prime is 133143522961. The next prime is 133143523103. The reversal of 133143523081 is 180325341331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71548225225 + 61595297856 = 267485^2 + 248184^2 .
It is a cyclic number.
It is not a de Polignac number, because 133143523081 - 29 = 133143522569 is a prime.
It is a super-2 number, since 2×1331435230812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133149523081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66571761540 + 66571761541.
It is an arithmetic number, because the mean of its divisors is an integer number (66571761541).
Almost surely, 2133143523081 is an apocalyptic number.
It is an amenable number.
133143523081 is a deficient number, since it is larger than the sum of its proper divisors (1).
133143523081 is an equidigital number, since it uses as much as digits as its factorization.
133143523081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 34.
The spelling of 133143523081 in words is "one hundred thirty-three billion, one hundred forty-three million, five hundred twenty-three thousand, eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •