Base | Representation |
---|---|
bin | 111110000000010000… |
… | …0100110011010001111 |
3 | 110201200121222110200101 |
4 | 1330000200212122033 |
5 | 4140144022011421 |
6 | 141100332511531 |
7 | 12422433564034 |
oct | 1740040463217 |
9 | 421617873611 |
10 | 133152532111 |
11 | 51519151175 |
12 | 2198061b5a7 |
13 | c730063651 |
14 | 663205938b |
15 | 36e49d7191 |
hex | 1f0082668f |
133152532111 has 2 divisors, whose sum is σ = 133152532112. Its totient is φ = 133152532110.
The previous prime is 133152532091. The next prime is 133152532129. The reversal of 133152532111 is 111235251331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133152532111 - 215 = 133152499343 is a prime.
It is a super-2 number, since 2×1331525321112 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133152532111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133152532151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66576266055 + 66576266056.
It is an arithmetic number, because the mean of its divisors is an integer number (66576266056).
Almost surely, 2133152532111 is an apocalyptic number.
133152532111 is a deficient number, since it is larger than the sum of its proper divisors (1).
133152532111 is an equidigital number, since it uses as much as digits as its factorization.
133152532111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2700, while the sum is 28.
Adding to 133152532111 its reverse (111235251331), we get a palindrome (244387783442).
The spelling of 133152532111 in words is "one hundred thirty-three billion, one hundred fifty-two million, five hundred thirty-two thousand, one hundred eleven".
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