| Base | Representation |
|---|---|
| bin | 11000110011010011… |
| … | …11000011100000000 |
| 3 | 1021100222002220100000 |
| 4 | 30121221320130000 |
| 5 | 204232204430420 |
| 6 | 10041133200000 |
| 7 | 650652164511 |
| oct | 143151703400 |
| 9 | 37328086300 |
| 10 | 13315311360 |
| 11 | 571316755a |
| 12 | 26b7330000 |
| 13 | 1342800a80 |
| 14 | 9045a6a08 |
| 15 | 52de87690 |
| hex | 319a78700 |
13315311360 has 864 divisors, whose sum is σ = 53435229120. Its totient is φ = 3153199104.
The previous prime is 13315311349. The next prime is 13315311371. The reversal of 13315311360 is 6311351331.
13315311360 is a `hidden beast` number, since 1 + 3 + 315 + 311 + 36 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (13315311349) and next prime (13315311371).
It is a tau number, because it is divible by the number of its divisors (864).
It is a super-2 number, since 2×133153113602 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 149610196 + ... + 149610284.
It is an arithmetic number, because the mean of its divisors is an integer number (61846330).
Almost surely, 213315311360 is an apocalyptic number.
13315311360 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13315311360, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26717614560).
13315311360 is an abundant number, since it is smaller than the sum of its proper divisors (40119917760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13315311360 is an equidigital number, since it uses as much as digits as its factorization.
13315311360 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 175 (or 149 counting only the distinct ones).
The product of its (nonzero) digits is 2430, while the sum is 27.
Adding to 13315311360 its reverse (6311351331), we get a palindrome (19626662691).
The spelling of 13315311360 in words is "thirteen billion, three hundred fifteen million, three hundred eleven thousand, three hundred sixty".
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