Base | Representation |
---|---|
bin | 10011011000000101100… |
… | …001011001010011100011 |
3 | 11201021220210022112110121 |
4 | 103120011201121103203 |
5 | 133303434310032433 |
6 | 2455410402341111 |
7 | 165125421344656 |
oct | 23300541312343 |
9 | 4637823275417 |
10 | 1331532502243 |
11 | 4737774258a9 |
12 | 19608765a797 |
13 | 98741b216a8 |
14 | 4863735789d |
15 | 24982368c2d |
hex | 136058594e3 |
1331532502243 has 2 divisors, whose sum is σ = 1331532502244. Its totient is φ = 1331532502242.
The previous prime is 1331532502207. The next prime is 1331532502283. The reversal of 1331532502243 is 3422052351331.
It is a weak prime.
It is an emirp because it is prime and its reverse (3422052351331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1331532502243 - 29 = 1331532501731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1331532502199 and 1331532502208.
It is not a weakly prime, because it can be changed into another prime (1331532502283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665766251121 + 665766251122.
It is an arithmetic number, because the mean of its divisors is an integer number (665766251122).
Almost surely, 21331532502243 is an apocalyptic number.
1331532502243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331532502243 is an equidigital number, since it uses as much as digits as its factorization.
1331532502243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 1331532502243 its reverse (3422052351331), we get a palindrome (4753584853574).
The spelling of 1331532502243 in words is "one trillion, three hundred thirty-one billion, five hundred thirty-two million, five hundred two thousand, two hundred forty-three".
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