Base | Representation |
---|---|
bin | 1100000111000111101010… |
… | …1100000101000101011101 |
3 | 1202011001002210011102112012 |
4 | 3001301322230011011131 |
5 | 3221134100442234432 |
6 | 44153255040121005 |
7 | 2543040134560565 |
oct | 301617254050535 |
9 | 52131083142465 |
10 | 13316456993117 |
11 | 42745288a4553 |
12 | 15b099a606165 |
13 | 757976147c75 |
14 | 34073ca97da5 |
15 | 1815d1a0bcb2 |
hex | c1c7ab0515d |
13316456993117 has 2 divisors, whose sum is σ = 13316456993118. Its totient is φ = 13316456993116.
The previous prime is 13316456993053. The next prime is 13316456993219. The reversal of 13316456993117 is 71139965461331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12695353806916 + 621103186201 = 3563054^2 + 788101^2 .
It is a cyclic number.
It is not a de Polignac number, because 13316456993117 - 26 = 13316456993053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13316456992117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6658228496558 + 6658228496559.
It is an arithmetic number, because the mean of its divisors is an integer number (6658228496559).
Almost surely, 213316456993117 is an apocalyptic number.
It is an amenable number.
13316456993117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13316456993117 is an equidigital number, since it uses as much as digits as its factorization.
13316456993117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11022480, while the sum is 59.
The spelling of 13316456993117 in words is "thirteen trillion, three hundred sixteen billion, four hundred fifty-six million, nine hundred ninety-three thousand, one hundred seventeen".
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