Base | Representation |
---|---|
bin | 111110000000101001… |
… | …0100001111110001101 |
3 | 110201201112121110102222 |
4 | 1330001102201332031 |
5 | 4140210344334013 |
6 | 141101521225125 |
7 | 12422653050326 |
oct | 1740122417615 |
9 | 421645543388 |
10 | 133165621133 |
11 | 51525581146 |
12 | 21984a921a5 |
13 | c73299722c |
14 | 6633aa544d |
15 | 36e5c20508 |
hex | 1f014a1f8d |
133165621133 has 2 divisors, whose sum is σ = 133165621134. Its totient is φ = 133165621132.
The previous prime is 133165621111. The next prime is 133165621151. The reversal of 133165621133 is 331126561331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113945403364 + 19220217769 = 337558^2 + 138637^2 .
It is a cyclic number.
It is not a de Polignac number, because 133165621133 - 212 = 133165617037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133165621093 and 133165621102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133165621733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66582810566 + 66582810567.
It is an arithmetic number, because the mean of its divisors is an integer number (66582810567).
Almost surely, 2133165621133 is an apocalyptic number.
It is an amenable number.
133165621133 is a deficient number, since it is larger than the sum of its proper divisors (1).
133165621133 is an equidigital number, since it uses as much as digits as its factorization.
133165621133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 29160, while the sum is 35.
The spelling of 133165621133 in words is "one hundred thirty-three billion, one hundred sixty-five million, six hundred twenty-one thousand, one hundred thirty-three".
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