Base | Representation |
---|---|
bin | 1100000111001011101100… |
… | …1111101000000110101111 |
3 | 1202011010220021010120221212 |
4 | 3001302323033220012233 |
5 | 3221143310223202143 |
6 | 44153554325545035 |
7 | 2543106025462034 |
oct | 301627317500657 |
9 | 52133807116855 |
10 | 13317540053423 |
11 | 4274a34199811 |
12 | 15b104127517b |
13 | 757ab9647458 |
14 | 34080286738b |
15 | 181646b48918 |
hex | c1cbb3e81af |
13317540053423 has 2 divisors, whose sum is σ = 13317540053424. Its totient is φ = 13317540053422.
The previous prime is 13317540053393. The next prime is 13317540053431. The reversal of 13317540053423 is 32435004571331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13317540053423 - 218 = 13317539791279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13317540053023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6658770026711 + 6658770026712.
It is an arithmetic number, because the mean of its divisors is an integer number (6658770026712).
Almost surely, 213317540053423 is an apocalyptic number.
13317540053423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13317540053423 is an equidigital number, since it uses as much as digits as its factorization.
13317540053423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 453600, while the sum is 41.
The spelling of 13317540053423 in words is "thirteen trillion, three hundred seventeen billion, five hundred forty million, fifty-three thousand, four hundred twenty-three".
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