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13318991533 is a prime number
BaseRepresentation
bin11000110011101111…
…11010111010101101
31021101020000212120201
430121313322322231
5204234130212113
610041344113501
7651025363051
oct143167727255
937336025521
1013318991533
115715250521
1226b8605891
1313434bbba3
14904c83c61
1552e462cdd
hex319dfaead

13318991533 has 2 divisors, whose sum is σ = 13318991534. Its totient is φ = 13318991532.

The previous prime is 13318991519. The next prime is 13318991549. The reversal of 13318991533 is 33519981331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8554955049 + 4764036484 = 92493^2 + 69022^2 .

It is an emirp because it is prime and its reverse (33519981331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13318991533 - 213 = 13318983341 is a prime.

It is a super-2 number, since 2×133189915332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13318991563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6659495766 + 6659495767.

It is an arithmetic number, because the mean of its divisors is an integer number (6659495767).

Almost surely, 213318991533 is an apocalyptic number.

It is an amenable number.

13318991533 is a deficient number, since it is larger than the sum of its proper divisors (1).

13318991533 is an equidigital number, since it uses as much as digits as its factorization.

13318991533 is an evil number, because the sum of its binary digits is even.

The product of its digits is 262440, while the sum is 46.

The spelling of 13318991533 in words is "thirteen billion, three hundred eighteen million, nine hundred ninety-one thousand, five hundred thirty-three".