Base | Representation |
---|---|
bin | 11000110011111000… |
… | …00001000111011001 |
3 | 1021101022001102210011 |
4 | 30121330001013121 |
5 | 204234414043442 |
6 | 10041423121521 |
7 | 651040455124 |
oct | 143174010731 |
9 | 37338042704 |
10 | 13320065497 |
11 | 57159143a2 |
12 | 26b8a432a1 |
13 | 13437a697b |
14 | 9050833bb |
15 | 52e5c6117 |
hex | 319f011d9 |
13320065497 has 2 divisors, whose sum is σ = 13320065498. Its totient is φ = 13320065496.
The previous prime is 13320065489. The next prime is 13320065567. The reversal of 13320065497 is 79456002331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10897063321 + 2423002176 = 104389^2 + 49224^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320065497 - 23 = 13320065489 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320065467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660032748 + 6660032749.
It is an arithmetic number, because the mean of its divisors is an integer number (6660032749).
Almost surely, 213320065497 is an apocalyptic number.
It is an amenable number.
13320065497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320065497 is an equidigital number, since it uses as much as digits as its factorization.
13320065497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 13320065497 in words is "thirteen billion, three hundred twenty million, sixty-five thousand, four hundred ninety-seven".
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