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1332010120223 is a prime number
BaseRepresentation
bin10011011000100001111…
…111010111010000011111
311201100011002001001011102
4103120201333113100133
5133310424042321343
62455530023343315
7165143311132136
oct23304177272037
94640132031142
101332010120223
114739a1a95302
1219619b5b1b3b
13987b9a6b093
144868096491d
15249ae2603b8
hex13621fd741f

1332010120223 has 2 divisors, whose sum is σ = 1332010120224. Its totient is φ = 1332010120222.

The previous prime is 1332010120213. The next prime is 1332010120267. The reversal of 1332010120223 is 3220210102331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1332010120223 - 28 = 1332010119967 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1332010120195 and 1332010120204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332010120213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666005060111 + 666005060112.

It is an arithmetic number, because the mean of its divisors is an integer number (666005060112).

Almost surely, 21332010120223 is an apocalyptic number.

1332010120223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332010120223 is an equidigital number, since it uses as much as digits as its factorization.

1332010120223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1332010120223 its reverse (3220210102331), we get a palindrome (4552220222554).

The spelling of 1332010120223 in words is "one trillion, three hundred thirty-two billion, ten million, one hundred twenty thousand, two hundred twenty-three".