Base | Representation |
---|---|
bin | 10011011000100001111… |
… | …111010111010000011111 |
3 | 11201100011002001001011102 |
4 | 103120201333113100133 |
5 | 133310424042321343 |
6 | 2455530023343315 |
7 | 165143311132136 |
oct | 23304177272037 |
9 | 4640132031142 |
10 | 1332010120223 |
11 | 4739a1a95302 |
12 | 19619b5b1b3b |
13 | 987b9a6b093 |
14 | 4868096491d |
15 | 249ae2603b8 |
hex | 13621fd741f |
1332010120223 has 2 divisors, whose sum is σ = 1332010120224. Its totient is φ = 1332010120222.
The previous prime is 1332010120213. The next prime is 1332010120267. The reversal of 1332010120223 is 3220210102331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1332010120223 - 28 = 1332010119967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1332010120195 and 1332010120204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332010120213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666005060111 + 666005060112.
It is an arithmetic number, because the mean of its divisors is an integer number (666005060112).
Almost surely, 21332010120223 is an apocalyptic number.
1332010120223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332010120223 is an equidigital number, since it uses as much as digits as its factorization.
1332010120223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1332010120223 its reverse (3220210102331), we get a palindrome (4552220222554).
The spelling of 1332010120223 in words is "one trillion, three hundred thirty-two billion, ten million, one hundred twenty thousand, two hundred twenty-three".
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