Base | Representation |
---|---|
bin | 111110000001101110… |
… | …1010011100101001001 |
3 | 110201211002001201010212 |
4 | 1330003131103211021 |
5 | 4140244203001301 |
6 | 141105301050505 |
7 | 12423604214624 |
oct | 1740335234511 |
9 | 421732051125 |
10 | 133202000201 |
11 | 51544069296 |
12 | 219950b6a35 |
13 | c73a3938ca |
14 | 6638854dbb |
15 | 36e90094bb |
hex | 1f03753949 |
133202000201 has 2 divisors, whose sum is σ = 133202000202. Its totient is φ = 133202000200.
The previous prime is 133202000149. The next prime is 133202000207. The reversal of 133202000201 is 102000202331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132970351801 + 231648400 = 364651^2 + 15220^2 .
It is an emirp because it is prime and its reverse (102000202331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133202000201 - 218 = 133201738057 is a prime.
It is not a weakly prime, because it can be changed into another prime (133202000207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601000100 + 66601000101.
It is an arithmetic number, because the mean of its divisors is an integer number (66601000101).
Almost surely, 2133202000201 is an apocalyptic number.
It is an amenable number.
133202000201 is a deficient number, since it is larger than the sum of its proper divisors (1).
133202000201 is an equidigital number, since it uses as much as digits as its factorization.
133202000201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 133202000201 its reverse (102000202331), we get a palindrome (235202202532).
The spelling of 133202000201 in words is "one hundred thirty-three billion, two hundred two million, two hundred one", and thus it is an aban number.
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