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133202000201 is a prime number
BaseRepresentation
bin111110000001101110…
…1010011100101001001
3110201211002001201010212
41330003131103211021
54140244203001301
6141105301050505
712423604214624
oct1740335234511
9421732051125
10133202000201
1151544069296
12219950b6a35
13c73a3938ca
146638854dbb
1536e90094bb
hex1f03753949

133202000201 has 2 divisors, whose sum is σ = 133202000202. Its totient is φ = 133202000200.

The previous prime is 133202000149. The next prime is 133202000207. The reversal of 133202000201 is 102000202331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132970351801 + 231648400 = 364651^2 + 15220^2 .

It is an emirp because it is prime and its reverse (102000202331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133202000201 - 218 = 133201738057 is a prime.

It is not a weakly prime, because it can be changed into another prime (133202000207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601000100 + 66601000101.

It is an arithmetic number, because the mean of its divisors is an integer number (66601000101).

Almost surely, 2133202000201 is an apocalyptic number.

It is an amenable number.

133202000201 is a deficient number, since it is larger than the sum of its proper divisors (1).

133202000201 is an equidigital number, since it uses as much as digits as its factorization.

133202000201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 133202000201 its reverse (102000202331), we get a palindrome (235202202532).

The spelling of 133202000201 in words is "one hundred thirty-three billion, two hundred two million, two hundred one", and thus it is an aban number.