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13320210013414 = 26660105006707
BaseRepresentation
bin1100000111010101101001…
…1000101101110011100110
31202011101210100010121111221
43001311122120231303212
53221214242230412124
644155115304250554
72543232135661663
oct301653230556346
952141710117457
1013320210013414
114276084328217
1215b1667470a5a
13758123843935
143409b72baa6a
15181751247ce4
hexc1d5a62dce6

13320210013414 has 4 divisors (see below), whose sum is σ = 19980315020124. Its totient is φ = 6660105006706.

The previous prime is 13320210013393. The next prime is 13320210013417. The reversal of 13320210013414 is 41431001202331.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13320210013417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3330052503352 + ... + 3330052503355.

It is an arithmetic number, because the mean of its divisors is an integer number (4995078755031).

Almost surely, 213320210013414 is an apocalyptic number.

13320210013414 is a deficient number, since it is larger than the sum of its proper divisors (6660105006710).

13320210013414 is an equidigital number, since it uses as much as digits as its factorization.

13320210013414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6660105006709.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13320210013414 its reverse (41431001202331), we get a palindrome (54751211215745).

The spelling of 13320210013414 in words is "thirteen trillion, three hundred twenty billion, two hundred ten million, thirteen thousand, four hundred fourteen".

Divisors: 1 2 6660105006707 13320210013414