Base | Representation |
---|---|
bin | 1100000111010101101001… |
… | …1000110010001101010001 |
3 | 1202011101210100011112020121 |
4 | 3001311122120302031101 |
5 | 3221214242232001231 |
6 | 44155115304510241 |
7 | 2543232136065355 |
oct | 301653230621521 |
9 | 52141710145217 |
10 | 13320210031441 |
11 | 427608433a815 |
12 | 15b166747b381 |
13 | 75812384bbc1 |
14 | 3409b72c3465 |
15 | 18175124d311 |
hex | c1d5a632351 |
13320210031441 has 2 divisors, whose sum is σ = 13320210031442. Its totient is φ = 13320210031440.
The previous prime is 13320210031417. The next prime is 13320210031451. The reversal of 13320210031441 is 14413001202331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7222871251600 + 6097338779841 = 2687540^2 + 2469279^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320210031441 - 27 = 13320210031313 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320210031411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660105015720 + 6660105015721.
It is an arithmetic number, because the mean of its divisors is an integer number (6660105015721).
Almost surely, 213320210031441 is an apocalyptic number.
It is an amenable number.
13320210031441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320210031441 is an equidigital number, since it uses as much as digits as its factorization.
13320210031441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13320210031441 its reverse (14413001202331), we get a palindrome (27733211233772).
The spelling of 13320210031441 in words is "thirteen trillion, three hundred twenty billion, two hundred ten million, thirty-one thousand, four hundred forty-one".
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