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133202101020133 is a prime number
BaseRepresentation
bin11110010010010110000111…
…111010100010010111100101
3122110121222220110000010111211
4132102112013322202113211
5114424340400330121013
61151144111143431421
740025351144245645
oct3622260772422745
9573558813003454
10133202101020133
113949576a4aa682
1212b33562155571
135942b9a78b522
1424c703220a525
15105ed5b92b23d
hex792587ea25e5

133202101020133 has 2 divisors, whose sum is σ = 133202101020134. Its totient is φ = 133202101020132.

The previous prime is 133202101020019. The next prime is 133202101020137. The reversal of 133202101020133 is 331020101202331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122445688608324 + 10756412411809 = 11065518^2 + 3279697^2 .

It is an emirp because it is prime and its reverse (331020101202331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133202101020133 - 29 = 133202101019621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133202101020137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601050510066 + 66601050510067.

It is an arithmetic number, because the mean of its divisors is an integer number (66601050510067).

Almost surely, 2133202101020133 is an apocalyptic number.

It is an amenable number.

133202101020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

133202101020133 is an equidigital number, since it uses as much as digits as its factorization.

133202101020133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 133202101020133 its reverse (331020101202331), we get a palindrome (464222202222464).

The spelling of 133202101020133 in words is "one hundred thirty-three trillion, two hundred two billion, one hundred one million, twenty thousand, one hundred thirty-three".