Base | Representation |
---|---|
bin | 11110010010010110000111… |
… | …111010100010100101001111 |
3 | 122110121222220110000011201012 |
4 | 132102112013322202211033 |
5 | 114424340400330133012 |
6 | 1151144111143435435 |
7 | 40025351144251334 |
oct | 3622260772424517 |
9 | 573558813004635 |
10 | 133202101021007 |
11 | 3949576a5002a7 |
12 | 12b33562155b7b |
13 | 5942b9a78ba45 |
14 | 24c703220a98b |
15 | 105ed5b92b622 |
hex | 792587ea294f |
133202101021007 has 2 divisors, whose sum is σ = 133202101021008. Its totient is φ = 133202101021006.
The previous prime is 133202101020907. The next prime is 133202101021039. The reversal of 133202101021007 is 700120101202331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133202101021007 - 222 = 133202096826703 is a prime.
It is a super-3 number, since 3×1332021010210073 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133202101021607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601050510503 + 66601050510504.
It is an arithmetic number, because the mean of its divisors is an integer number (66601050510504).
Almost surely, 2133202101021007 is an apocalyptic number.
133202101021007 is a deficient number, since it is larger than the sum of its proper divisors (1).
133202101021007 is an equidigital number, since it uses as much as digits as its factorization.
133202101021007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 133202101021007 its reverse (700120101202331), we get a palindrome (833322202223338).
The spelling of 133202101021007 in words is "one hundred thirty-three trillion, two hundred two billion, one hundred one million, twenty-one thousand, seven".
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