Base | Representation |
---|---|
bin | 1100000111010101101100… |
… | …0110100110010101011010 |
3 | 1202011101211011202200212011 |
4 | 3001311123012212111122 |
5 | 3221214303320311214 |
6 | 44155120414140134 |
7 | 2543232343136050 |
oct | 301653306462532 |
9 | 52141734680764 |
10 | 13320222041434 |
11 | 42760900a3030 |
12 | 15b166b4b164a |
13 | 7581261955c9 |
14 | 3409b8b2c1d0 |
15 | 181752321ac4 |
hex | c1d5b1a655a |
13320222041434 has 256 divisors, whose sum is σ = 26841177391104. Its totient is φ = 4805110252800.
The previous prime is 13320222041429. The next prime is 13320222041471. The reversal of 13320222041434 is 43414022202331.
13320222041434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13320222041396 and 13320222041405.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 5443489599 + ... + 5443492045.
It is an arithmetic number, because the mean of its divisors is an integer number (104848349184).
Almost surely, 213320222041434 is an apocalyptic number.
13320222041434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13320222041434 is an abundant number, since it is smaller than the sum of its proper divisors (13520955349670).
13320222041434 is a wasteful number, since it uses less digits than its factorization.
13320222041434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2921.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13320222041434 its reverse (43414022202331), we get a palindrome (56734244243765).
The spelling of 13320222041434 in words is "thirteen trillion, three hundred twenty billion, two hundred twenty-two million, forty-one thousand, four hundred thirty-four".
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