Base | Representation |
---|---|
bin | 1100000111010101101100… |
… | …0110100110010101111111 |
3 | 1202011101211011202200220112 |
4 | 3001311123012212111333 |
5 | 3221214303320311341 |
6 | 44155120414140235 |
7 | 2543232343136132 |
oct | 301653306462577 |
9 | 52141734680815 |
10 | 13320222041471 |
11 | 42760900a3064 |
12 | 15b166b4b167b |
13 | 758126195627 |
14 | 3409b8b2c219 |
15 | 181752321aeb |
hex | c1d5b1a657f |
13320222041471 has 2 divisors, whose sum is σ = 13320222041472. Its totient is φ = 13320222041470.
The previous prime is 13320222041429. The next prime is 13320222041479. The reversal of 13320222041471 is 17414022202331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13320222041471 - 26 = 13320222041407 is a prime.
It is a super-3 number, since 3×133202220414713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13320222041479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660111020735 + 6660111020736.
It is an arithmetic number, because the mean of its divisors is an integer number (6660111020736).
Almost surely, 213320222041471 is an apocalyptic number.
13320222041471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320222041471 is an equidigital number, since it uses as much as digits as its factorization.
13320222041471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
The spelling of 13320222041471 in words is "thirteen trillion, three hundred twenty billion, two hundred twenty-two million, forty-one thousand, four hundred seventy-one".
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