Base | Representation |
---|---|
bin | 1100000111010101101110… |
… | …0100111110000110111011 |
3 | 1202011101211201202012020211 |
4 | 3001311123210332012323 |
5 | 3221214312340100011 |
6 | 44155121300531551 |
7 | 2543232500616022 |
oct | 301653344760673 |
9 | 52141751665224 |
10 | 13320230003131 |
11 | 4276094640847 |
12 | 15b16720b0bb7 |
13 | 758127a2247c |
14 | 3409b9c018b9 |
15 | 181752d95b21 |
hex | c1d5b93e1bb |
13320230003131 has 2 divisors, whose sum is σ = 13320230003132. Its totient is φ = 13320230003130.
The previous prime is 13320230003107. The next prime is 13320230003149. The reversal of 13320230003131 is 13130003202331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13320230003131 - 239 = 12770474189243 is a prime.
It is a super-3 number, since 3×133202300031313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13320230003831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660115001565 + 6660115001566.
It is an arithmetic number, because the mean of its divisors is an integer number (6660115001566).
Almost surely, 213320230003131 is an apocalyptic number.
13320230003131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320230003131 is an equidigital number, since it uses as much as digits as its factorization.
13320230003131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13320230003131 its reverse (13130003202331), we get a palindrome (26450233205462).
The spelling of 13320230003131 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty million, three thousand, one hundred thirty-one".
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