Base | Representation |
---|---|
bin | 1100000111010101101110… |
… | …1110001010110000100011 |
3 | 1202011101211220021200200021 |
4 | 3001311123232022300203 |
5 | 3221214313444223433 |
6 | 44155121424334311 |
7 | 2543232530250346 |
oct | 301653356126043 |
9 | 52141756250607 |
10 | 13320232414243 |
11 | 4276095a382a7 |
12 | 15b1672a74397 |
13 | 758128387a71 |
14 | 3409ba26c45d |
15 | 1817531c022d |
hex | c1d5bb8ac23 |
13320232414243 has 2 divisors, whose sum is σ = 13320232414244. Its totient is φ = 13320232414242.
The previous prime is 13320232414201. The next prime is 13320232414301. The reversal of 13320232414243 is 34241423202331.
13320232414243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13320232414243 - 29 = 13320232413731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13320232414199 and 13320232414208.
It is not a weakly prime, because it can be changed into another prime (13320232414543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660116207121 + 6660116207122.
It is an arithmetic number, because the mean of its divisors is an integer number (6660116207122).
Almost surely, 213320232414243 is an apocalyptic number.
13320232414243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320232414243 is an equidigital number, since it uses as much as digits as its factorization.
13320232414243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 13320232414243 its reverse (34241423202331), we get a palindrome (47561655616574).
The spelling of 13320232414243 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-two million, four hundred fourteen thousand, two hundred forty-three".
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