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13320232414243 is a prime number
BaseRepresentation
bin1100000111010101101110…
…1110001010110000100011
31202011101211220021200200021
43001311123232022300203
53221214313444223433
644155121424334311
72543232530250346
oct301653356126043
952141756250607
1013320232414243
114276095a382a7
1215b1672a74397
13758128387a71
143409ba26c45d
151817531c022d
hexc1d5bb8ac23

13320232414243 has 2 divisors, whose sum is σ = 13320232414244. Its totient is φ = 13320232414242.

The previous prime is 13320232414201. The next prime is 13320232414301. The reversal of 13320232414243 is 34241423202331.

13320232414243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13320232414243 - 29 = 13320232413731 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13320232414199 and 13320232414208.

It is not a weakly prime, because it can be changed into another prime (13320232414543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660116207121 + 6660116207122.

It is an arithmetic number, because the mean of its divisors is an integer number (6660116207122).

Almost surely, 213320232414243 is an apocalyptic number.

13320232414243 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320232414243 is an equidigital number, since it uses as much as digits as its factorization.

13320232414243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 13320232414243 its reverse (34241423202331), we get a palindrome (47561655616574).

The spelling of 13320232414243 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-two million, four hundred fourteen thousand, two hundred forty-three".