Base | Representation |
---|---|
bin | 1100000111010101111111… |
… | …0100010011100011110111 |
3 | 1202011102000200120220202020 |
4 | 3001311133310103203313 |
5 | 3221214434042211043 |
6 | 44155132321244223 |
7 | 2543234323323624 |
oct | 301653764234367 |
9 | 52142020526666 |
10 | 13320301132023 |
11 | 4276120802a56 |
12 | 15b1691a93673 |
13 | 758139697a82 |
14 | 3409c543934b |
15 | 181759245e83 |
hex | c1d5fd138f7 |
13320301132023 has 32 divisors (see below), whose sum is σ = 18179477153280. Its totient is φ = 8672752435200.
The previous prime is 13320301132003. The next prime is 13320301132037. The reversal of 13320301132023 is 32023110302331.
It is not a de Polignac number, because 13320301132023 - 234 = 13303121262839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13320301131984 and 13320301132002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13320301132003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25119223 + ... + 25644023.
It is an arithmetic number, because the mean of its divisors is an integer number (568108661040).
Almost surely, 213320301132023 is an apocalyptic number.
13320301132023 is a deficient number, since it is larger than the sum of its proper divisors (4859176021257).
13320301132023 is a wasteful number, since it uses less digits than its factorization.
13320301132023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 525799.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13320301132023 its reverse (32023110302331), we get a palindrome (45343411434354).
The spelling of 13320301132023 in words is "thirteen trillion, three hundred twenty billion, three hundred one million, one hundred thirty-two thousand, twenty-three".
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