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13320310947877 is a prime number
BaseRepresentation
bin1100000111010110000001…
…1001110000000000100101
31202011102001101001121120101
43001311200121300000211
53221214444100313002
644155133311504101
72543234502625363
oct301654031600045
952142041047511
1013320310947877
1142761262a782a
1215b1695228031
1375813b72387b
143409c6872633
1518175a034587
hexc1d60670025

13320310947877 has 2 divisors, whose sum is σ = 13320310947878. Its totient is φ = 13320310947876.

The previous prime is 13320310947829. The next prime is 13320310947899. The reversal of 13320310947877 is 77874901302331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12492591284196 + 827719663681 = 3534486^2 + 909791^2 .

It is a cyclic number.

It is not a de Polignac number, because 13320310947877 - 211 = 13320310945829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13320310917877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660155473938 + 6660155473939.

It is an arithmetic number, because the mean of its divisors is an integer number (6660155473939).

Almost surely, 213320310947877 is an apocalyptic number.

It is an amenable number.

13320310947877 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320310947877 is an equidigital number, since it uses as much as digits as its factorization.

13320310947877 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5334336, while the sum is 55.

The spelling of 13320310947877 in words is "thirteen trillion, three hundred twenty billion, three hundred ten million, nine hundred forty-seven thousand, eight hundred seventy-seven".