Base | Representation |
---|---|
bin | 1100000111010110000001… |
… | …1110011100001110010001 |
3 | 1202011102001110101002100221 |
4 | 3001311200132130032101 |
5 | 3221214444404140203 |
6 | 44155133354113041 |
7 | 2543234516236423 |
oct | 301654036341621 |
9 | 52142043332327 |
10 | 13320312177553 |
11 | 4276126a67697 |
12 | 15b169571b781 |
13 | 75813ba644a4 |
14 | 3409c6ab2813 |
15 | 18175a1c8abd |
hex | c1d6079c391 |
13320312177553 has 2 divisors, whose sum is σ = 13320312177554. Its totient is φ = 13320312177552.
The previous prime is 13320312177551. The next prime is 13320312177619. The reversal of 13320312177553 is 35577121302331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12557051349649 + 763260827904 = 3543593^2 + 873648^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320312177553 - 21 = 13320312177551 is a prime.
Together with 13320312177551, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13320312177551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660156088776 + 6660156088777.
It is an arithmetic number, because the mean of its divisors is an integer number (6660156088777).
Almost surely, 213320312177553 is an apocalyptic number.
It is an amenable number.
13320312177553 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320312177553 is an equidigital number, since it uses as much as digits as its factorization.
13320312177553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 396900, while the sum is 43.
Adding to 13320312177553 its reverse (35577121302331), we get a palindrome (48897433479884).
The spelling of 13320312177553 in words is "thirteen trillion, three hundred twenty billion, three hundred twelve million, one hundred seventy-seven thousand, five hundred fifty-three".
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