1332033302497 has 2 divisors, whose sum is σ = 1332033302498. Its totient is φ = 1332033302496.

The previous prime is 1332033302491. The next prime is 1332033302503. The reversal of 1332033302497 is 7942033302331.

It is a balanced prime because it is at equal distance from previous prime (1332033302491) and next prime (1332033302503).

It can be written as a sum of positive squares in only one way, i.e., 943460599761 + 388572702736 = 971319^2 + 623356^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332033302497 - 2¹⁵ = 1332033269729 is a prime.

It is a super-2 number, since 2×1332033302497² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1332033302491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666016651248 + 666016651249.

It is an arithmetic number, because the mean of its divisors is an integer number (666016651249).

Almost surely, 2^{1332033302497} is an apocalyptic number.

It is an amenable number.

1332033302497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332033302497 is an equidigital number, since it uses as much as digits as its factorization.

1332033302497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 244944, while the sum is 40.

The spelling of 1332033302497 in words is "one trillion, three hundred thirty-two billion, thirty-three million, three hundred two thousand, four hundred ninety-seven".