1332043344431 has 2 divisors, whose sum is σ = 1332043344432. Its totient is φ = 1332043344430.

The previous prime is 1332043344421. The next prime is 1332043344517. The reversal of 1332043344431 is 1344433402331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1332043344431 - 2²⁶ = 1331976235567 is a prime.

It is a super-2 number, since 2×1332043344431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1332043344391 and 1332043344400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332043344421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666021672215 + 666021672216.

It is an arithmetic number, because the mean of its divisors is an integer number (666021672216).

Almost surely, 2^{1332043344431} is an apocalyptic number.

1332043344431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332043344431 is an equidigital number, since it uses as much as digits as its factorization.

1332043344431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 1332043344431 its reverse (1344433402331), we get a palindrome (2676476746762).

The spelling of 1332043344431 in words is "one trillion, three hundred thirty-two billion, forty-three million, three hundred forty-four thousand, four hundred thirty-one".