Search a number
-
+
133204343133240 = 23335533806961129
BaseRepresentation
bin11110010010011000001101…
…100011100001010000111000
3122110122012200200221021111000
4132102120031203201100320
5114424404443320230430
61151145121440005000
740025460541013601
oct3622301543412070
9573565620837430
10133204343133240
1139496710083415
1212b33a89000760
135943167146482
1424c71a5ccada8
15105ee3d6b5e60
hex79260d8e1438

133204343133240 has 256 divisors, whose sum is σ = 452411393040000. Its totient is φ = 34849462063104.

The previous prime is 133204343133227. The next prime is 133204343133283. The reversal of 133204343133240 is 42331343402331.

133204343133240 is a `hidden beast` number, since 1 + 3 + 320 + 4 + 3 + 4 + 3 + 1 + 3 + 324 + 0 = 666.

133204343133240 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 133204343133195 and 133204343133204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2179038996 + ... + 2179100124.

Almost surely, 2133204343133240 is an apocalyptic number.

133204343133240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133204343133240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (226205696520000).

133204343133240 is an abundant number, since it is smaller than the sum of its proper divisors (319207049906760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133204343133240 is a wasteful number, since it uses less digits than its factorization.

133204343133240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99271 (or 99261 counting only the distinct ones).

The product of its (nonzero) digits is 186624, while the sum is 36.

Adding to 133204343133240 its reverse (42331343402331), we get a palindrome (175535686535571).

The spelling of 133204343133240 in words is "one hundred thirty-three trillion, two hundred four billion, three hundred forty-three million, one hundred thirty-three thousand, two hundred forty".