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13320555050500 = 2253295928155411
BaseRepresentation
bin1100000111010110111011…
…1100111011011000000100
31202011102200101101022102021
43001311232330323120010
53221220444043104000
644155213431452524
72543243525516005
oct301655674733004
952142611338367
1013320555050500
114276241072735
1215b1742b27144
1375817a17cba9
14340a0b0551ac
151817716a111a
hexc1d6ef3b604

13320555050500 has 192 divisors, whose sum is σ = 30714827270400. Its totient is φ = 5039207040000.

The previous prime is 13320555050489. The next prime is 13320555050513. The reversal of 13320555050500 is 505055502331.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 240367795 + ... + 240423205.

It is an arithmetic number, because the mean of its divisors is an integer number (159973058700).

Almost surely, 213320555050500 is an apocalyptic number.

13320555050500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13320555050500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15357413635200).

13320555050500 is an abundant number, since it is smaller than the sum of its proper divisors (17394272219900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13320555050500 is a wasteful number, since it uses less digits than its factorization.

13320555050500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55799 (or 55787 counting only the distinct ones).

The product of its (nonzero) digits is 56250, while the sum is 34.

The spelling of 13320555050500 in words is "thirteen trillion, three hundred twenty billion, five hundred fifty-five million, fifty thousand, five hundred".