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13320555050513 is a prime number
BaseRepresentation
bin1100000111010110111011…
…1100111011011000010001
31202011102200101101022102202
43001311232330323120101
53221220444043104023
644155213431452545
72543243525516024
oct301655674733021
952142611338382
1013320555050513
114276241072747
1215b1742b27155
1375817a17cbb9
14340a0b0551bb
151817716a1128
hexc1d6ef3b611

13320555050513 has 2 divisors, whose sum is σ = 13320555050514. Its totient is φ = 13320555050512.

The previous prime is 13320555050489. The next prime is 13320555050531. The reversal of 13320555050513 is 31505055502331.

Together with next prime (13320555050531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12967899603409 + 352655447104 = 3601097^2 + 593848^2 .

It is a cyclic number.

It is not a de Polignac number, because 13320555050513 - 212 = 13320555046417 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13320555050213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660277525256 + 6660277525257.

It is an arithmetic number, because the mean of its divisors is an integer number (6660277525257).

Almost surely, 213320555050513 is an apocalyptic number.

It is an amenable number.

13320555050513 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320555050513 is an equidigital number, since it uses as much as digits as its factorization.

13320555050513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168750, while the sum is 38.

The spelling of 13320555050513 in words is "thirteen trillion, three hundred twenty billion, five hundred fifty-five million, fifty thousand, five hundred thirteen".