13320560117 has 2 divisors, whose sum is σ = 13320560118. Its totient is φ = 13320560116.

The previous prime is 13320560059. The next prime is 13320560129. The reversal of 13320560117 is 71106502331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12852530161 + 468029956 = 113369^2 + 21634^2 .

It is a cyclic number.

It is not a de Polignac number, because 13320560117 - 2¹⁰ = 13320559093 is a prime.

It is a super-2 number, since 2×13320560117² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13320560117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13320565117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660280058 + 6660280059.

It is an arithmetic number, because the mean of its divisors is an integer number (6660280059).

Almost surely, 2^13320560117 is an apocalyptic number.

It is an amenable number.

13320560117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320560117 is an equidigital number, since it uses as much as digits as its factorization.

13320560117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 29.

The spelling of 13320560117 in words is "thirteen billion, three hundred twenty million, five hundred sixty thousand, one hundred seventeen".