Base | Representation |
---|---|
bin | 111110000001111010… |
… | …0011100000001000111 |
3 | 110201211111110210012122 |
4 | 1330003310130001013 |
5 | 4140302231022241 |
6 | 141110035040155 |
7 | 12424006601555 |
oct | 1740364340107 |
9 | 421744423178 |
10 | 133208064071 |
11 | 51547530155 |
12 | 2199714005b |
13 | c73b7079b4 |
14 | 6639592bd5 |
15 | 36e980604b |
hex | 1f03d1c047 |
133208064071 has 2 divisors, whose sum is σ = 133208064072. Its totient is φ = 133208064070.
The previous prime is 133208063987. The next prime is 133208064131. The reversal of 133208064071 is 170460802331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133208064071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133208064971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66604032035 + 66604032036.
It is an arithmetic number, because the mean of its divisors is an integer number (66604032036).
Almost surely, 2133208064071 is an apocalyptic number.
133208064071 is a deficient number, since it is larger than the sum of its proper divisors (1).
133208064071 is an equidigital number, since it uses as much as digits as its factorization.
133208064071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 133208064071 in words is "one hundred thirty-three billion, two hundred eight million, sixty-four thousand, seventy-one".
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