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1332107960317 is a prime number
BaseRepresentation
bin10011011000100111110…
…100100101111111111101
311201100101220010211112121
4103120213310211333331
5133311124114212232
62455543440402541
7165145606560211
oct23304764457775
94640356124477
101332107960317
11473a42240a92
12196208316451
1398804106724
144868d952941
15249b7b39d97
hex13627d25ffd

1332107960317 has 2 divisors, whose sum is σ = 1332107960318. Its totient is φ = 1332107960316.

The previous prime is 1332107960303. The next prime is 1332107960329. The reversal of 1332107960317 is 7130697012331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 774926329401 + 557181630916 = 880299^2 + 746446^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1332107960317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332107960347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666053980158 + 666053980159.

It is an arithmetic number, because the mean of its divisors is an integer number (666053980159).

Almost surely, 21332107960317 is an apocalyptic number.

It is an amenable number.

1332107960317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332107960317 is an equidigital number, since it uses as much as digits as its factorization.

1332107960317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 142884, while the sum is 43.

The spelling of 1332107960317 in words is "one trillion, three hundred thirty-two billion, one hundred seven million, nine hundred sixty thousand, three hundred seventeen".