Base | Representation |
---|---|
bin | 111110000001111111… |
… | …1101001000011000111 |
3 | 110201211200222222221221 |
4 | 1330003333221003013 |
5 | 4140304004013111 |
6 | 141110222021211 |
7 | 12424043553253 |
oct | 1740377510307 |
9 | 421750888857 |
10 | 133211001031 |
11 | 51549156799 |
12 | 21998117807 |
13 | c73c1c5744 |
14 | 6639b19263 |
15 | 36e9bd6371 |
hex | 1f03fe90c7 |
133211001031 has 2 divisors, whose sum is σ = 133211001032. Its totient is φ = 133211001030.
The previous prime is 133211001017. The next prime is 133211001059. The reversal of 133211001031 is 130100112331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133211001031 - 215 = 133210968263 is a prime.
It is a super-2 number, since 2×1332110010312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133211000996 and 133211001014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133211001071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66605500515 + 66605500516.
It is an arithmetic number, because the mean of its divisors is an integer number (66605500516).
Almost surely, 2133211001031 is an apocalyptic number.
133211001031 is a deficient number, since it is larger than the sum of its proper divisors (1).
133211001031 is an equidigital number, since it uses as much as digits as its factorization.
133211001031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 133211001031 its reverse (130100112331), we get a palindrome (263311113362).
The spelling of 133211001031 in words is "one hundred thirty-three billion, two hundred eleven million, one thousand, thirty-one".
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