Search a number
-
+
133211001221093 is a prime number
BaseRepresentation
bin11110010010011110011010…
…011010000110111111100101
3122110122211212201022011222102
4132102132122122012333211
5114430012112303033333
61151152142241541445
740026114535562465
oct3622363232067745
9573584781264872
10133211001221093
1139499517427364
1212b35226944885
135943988668623
1424c7638283ba5
1510601cce92ae8
hex79279a686fe5

133211001221093 has 2 divisors, whose sum is σ = 133211001221094. Its totient is φ = 133211001221092.

The previous prime is 133211001221059. The next prime is 133211001221131. The reversal of 133211001221093 is 390122100112331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121185905351809 + 12025095869284 = 11008447^2 + 3467722^2 .

It is a cyclic number.

It is not a de Polignac number, because 133211001221093 - 220 = 133211000172517 is a prime.

It is a super-2 number, since 2×1332110012210932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133211001221033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66605500610546 + 66605500610547.

It is an arithmetic number, because the mean of its divisors is an integer number (66605500610547).

Almost surely, 2133211001221093 is an apocalyptic number.

It is an amenable number.

133211001221093 is a deficient number, since it is larger than the sum of its proper divisors (1).

133211001221093 is an equidigital number, since it uses as much as digits as its factorization.

133211001221093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 133211001221093 in words is "one hundred thirty-three trillion, two hundred eleven billion, one million, two hundred twenty-one thousand, ninety-three".