Base | Representation |
---|---|
bin | 11000110100000000… |
… | …00000111000001101 |
3 | 1021101101000122211022 |
4 | 30122000000320031 |
5 | 204240201104401 |
6 | 10041501403525 |
7 | 651052410302 |
oct | 143200007015 |
9 | 37341018738 |
10 | 13321113101 |
11 | 571646a48a |
12 | 26b92695a5 |
13 | 1343a8275a |
14 | 9052770a9 |
15 | 52e73171b |
hex | 31a000e0d |
13321113101 has 2 divisors, whose sum is σ = 13321113102. Its totient is φ = 13321113100.
The previous prime is 13321113041. The next prime is 13321113107. The reversal of 13321113101 is 10131112331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9452895076 + 3868218025 = 97226^2 + 62195^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13321113101 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13321113101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321113107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660556550 + 6660556551.
It is an arithmetic number, because the mean of its divisors is an integer number (6660556551).
Almost surely, 213321113101 is an apocalyptic number.
It is an amenable number.
13321113101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321113101 is an equidigital number, since it uses as much as digits as its factorization.
13321113101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13321113101 its reverse (10131112331), we get a palindrome (23452225432).
The spelling of 13321113101 in words is "thirteen billion, three hundred twenty-one million, one hundred thirteen thousand, one hundred one".
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