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133212040143 = 3713487956191
BaseRepresentation
bin111110000010000001…
…1100110101111001111
3110201211202221210100120
41330010003212233033
54140304240241033
6141110300200023
712424055441610
oct1740403465717
9421752853316
10133212040143
11515497a6466
1221998539013
13c73c49a6c0
146639d09c07
1536e9d3e1b3
hex1f040e6bcf

133212040143 has 16 divisors (see below), whose sum is σ = 218604374016. Its totient is φ = 70265691360.

The previous prime is 133212040127. The next prime is 133212040187. The reversal of 133212040143 is 341040212331.

It is a happy number.

It is not a de Polignac number, because 133212040143 - 24 = 133212040127 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133212040123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 243977823 + ... + 243978368.

It is an arithmetic number, because the mean of its divisors is an integer number (13662773376).

Almost surely, 2133212040143 is an apocalyptic number.

133212040143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

133212040143 is a deficient number, since it is larger than the sum of its proper divisors (85392333873).

133212040143 is a wasteful number, since it uses less digits than its factorization.

133212040143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 487956214.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 133212040143 its reverse (341040212331), we get a palindrome (474252252474).

The spelling of 133212040143 in words is "one hundred thirty-three billion, two hundred twelve million, forty thousand, one hundred forty-three".

Divisors: 1 3 7 13 21 39 91 273 487956191 1463868573 3415693337 6343430483 10247080011 19030291449 44404013381 133212040143