Base | Representation |
---|---|
bin | 1100000111011001011011… |
… | …0101100010000011100111 |
3 | 1202011111102000111122112202 |
4 | 3001312112311202003213 |
5 | 3221223331343403143 |
6 | 44155404054005115 |
7 | 2543266232301266 |
oct | 301662665420347 |
9 | 52144360448482 |
10 | 13321224200423 |
11 | 42765548609a7 |
12 | 15b18ab04679b |
13 | 7582559aa3a9 |
14 | 340a71c7c5dd |
15 | 1817b02ccab8 |
hex | c1d96d620e7 |
13321224200423 has 2 divisors, whose sum is σ = 13321224200424. Its totient is φ = 13321224200422.
The previous prime is 13321224200387. The next prime is 13321224200461. The reversal of 13321224200423 is 32400242212331.
13321224200423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13321224200423 - 210 = 13321224199399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321224200023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660612100211 + 6660612100212.
It is an arithmetic number, because the mean of its divisors is an integer number (6660612100212).
Almost surely, 213321224200423 is an apocalyptic number.
13321224200423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321224200423 is an equidigital number, since it uses as much as digits as its factorization.
13321224200423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 13321224200423 its reverse (32400242212331), we get a palindrome (45721466412754).
The spelling of 13321224200423 in words is "thirteen trillion, three hundred twenty-one billion, two hundred twenty-four million, two hundred thousand, four hundred twenty-three".
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