Base | Representation |
---|---|
bin | 10011011000101001010… |
… | …100111010110001001011 |
3 | 11201100110122122201020220 |
4 | 103120221110322301023 |
5 | 133311202100224321 |
6 | 2455550141521123 |
7 | 165146334316035 |
oct | 23305124726113 |
9 | 4640418581226 |
10 | 1332133211211 |
11 | 473a555183a0 |
12 | 1962148731a3 |
13 | 98809407b9a |
14 | 48693046c55 |
15 | 249b9e769c6 |
hex | 1362953ac4b |
1332133211211 has 32 divisors (see below), whose sum is σ = 2032358059008. Its totient is φ = 768819594240.
The previous prime is 1332133211131. The next prime is 1332133211267. The reversal of 1332133211211 is 1121123312331.
It is not a de Polignac number, because 1332133211211 - 213 = 1332133203019 is a prime.
It is a super-2 number, since 2×13321332112112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1332133211291) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11549190 + ... + 11663963.
It is an arithmetic number, because the mean of its divisors is an integer number (63511189344).
Almost surely, 21332133211211 is an apocalyptic number.
1332133211211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1332133211211 is a deficient number, since it is larger than the sum of its proper divisors (700224847797).
1332133211211 is a wasteful number, since it uses less digits than its factorization.
1332133211211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23213251.
The product of its digits is 648, while the sum is 24.
Adding to 1332133211211 its reverse (1121123312331), we get a palindrome (2453256523542).
The spelling of 1332133211211 in words is "one trillion, three hundred thirty-two billion, one hundred thirty-three million, two hundred eleven thousand, two hundred eleven".
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