Base | Representation |
---|---|
bin | 111110000010000110… |
… | …0100001010010011101 |
3 | 110201211221100112002011 |
4 | 1330010030201102131 |
5 | 4140310340031432 |
6 | 141110422231221 |
7 | 12424114344133 |
oct | 1740414412235 |
9 | 421757315064 |
10 | 133214377117 |
11 | 51550052248 |
12 | 21999285511 |
13 | c73cb08323 |
14 | 663a357753 |
15 | 36ea151847 |
hex | 1f0432149d |
133214377117 has 2 divisors, whose sum is σ = 133214377118. Its totient is φ = 133214377116.
The previous prime is 133214377091. The next prime is 133214377147. The reversal of 133214377117 is 711773412331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118001868196 + 15212508921 = 343514^2 + 123339^2 .
It is a cyclic number.
It is not a de Polignac number, because 133214377117 - 235 = 98854638749 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133214377117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133214377147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66607188558 + 66607188559.
It is an arithmetic number, because the mean of its divisors is an integer number (66607188559).
Almost surely, 2133214377117 is an apocalyptic number.
It is an amenable number.
133214377117 is a deficient number, since it is larger than the sum of its proper divisors (1).
133214377117 is an equidigital number, since it uses as much as digits as its factorization.
133214377117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 74088, while the sum is 40.
Adding to 133214377117 its reverse (711773412331), we get a palindrome (844987789448).
The spelling of 133214377117 in words is "one hundred thirty-three billion, two hundred fourteen million, three hundred seventy-seven thousand, one hundred seventeen".
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