Search a number
-
+
13321511253013 is a prime number
BaseRepresentation
bin1100000111011010011111…
…1100100011010000010101
31202011112011000122102200011
43001312213330203100111
53221224423340044023
644155452350320221
72543306316224305
oct301664774432025
952145130572604
1013321511253013
1142766918a1847
1215b196b1b9071
137582a02c3bb2
14340a9c041605
151817ca5d050d
hexc1da7f23415

13321511253013 has 2 divisors, whose sum is σ = 13321511253014. Its totient is φ = 13321511253012.

The previous prime is 13321511252993. The next prime is 13321511253053. The reversal of 13321511253013 is 31035211512331.

13321511253013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12944150448804 + 377360804209 = 3597798^2 + 614297^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321511253013 - 29 = 13321511252501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13321511253053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660755626506 + 6660755626507.

It is an arithmetic number, because the mean of its divisors is an integer number (6660755626507).

Almost surely, 213321511253013 is an apocalyptic number.

It is an amenable number.

13321511253013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321511253013 is an equidigital number, since it uses as much as digits as its factorization.

13321511253013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 13321511253013 its reverse (31035211512331), we get a palindrome (44356722765344).

The spelling of 13321511253013 in words is "thirteen trillion, three hundred twenty-one billion, five hundred eleven million, two hundred fifty-three thousand, thirteen".