Base | Representation |
---|---|
bin | 1100000111011100010101… |
… | …0100101001101111110011 |
3 | 1202011120102101001011210121 |
4 | 3001313011110221233303 |
5 | 3221231431023012243 |
6 | 44200013314111111 |
7 | 2543324452362136 |
oct | 301670524515763 |
9 | 52146371034717 |
10 | 13322004110323 |
11 | 427691501a837 |
12 | 15b1a8827b497 |
13 | 75834b447b3c |
14 | 340b0769821d |
15 | 1818089d71ed |
hex | c1dc5529bf3 |
13322004110323 has 2 divisors, whose sum is σ = 13322004110324. Its totient is φ = 13322004110322.
The previous prime is 13322004110297. The next prime is 13322004110347. The reversal of 13322004110323 is 32301140022331.
It is a strong prime.
It is an emirp because it is prime and its reverse (32301140022331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13322004110323 - 221 = 13322002013171 is a prime.
It is not a weakly prime, because it can be changed into another prime (13322004114323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661002055161 + 6661002055162.
It is an arithmetic number, because the mean of its divisors is an integer number (6661002055162).
Almost surely, 213322004110323 is an apocalyptic number.
13322004110323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13322004110323 is an equidigital number, since it uses as much as digits as its factorization.
13322004110323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13322004110323 its reverse (32301140022331), we get a palindrome (45623144132654).
The spelling of 13322004110323 in words is "thirteen trillion, three hundred twenty-two billion, four million, one hundred ten thousand, three hundred twenty-three".
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