Base | Representation |
---|---|
bin | 11110010010100110111111… |
… | …010110101000111001001111 |
3 | 122110200201122120010120121111 |
4 | 132102212333112220321033 |
5 | 114430134443004043314 |
6 | 1151200304155312451 |
7 | 40026562006461463 |
oct | 3622467726507117 |
9 | 573621576116544 |
10 | 133220211002959 |
11 | 394a2413081833 |
12 | 12b36b7714b727 |
13 | 59447c57193b2 |
14 | 24c7c6d4a64a3 |
15 | 106056b7abec4 |
hex | 7929bf5a8e4f |
133220211002959 has 2 divisors, whose sum is σ = 133220211002960. Its totient is φ = 133220211002958.
The previous prime is 133220211002939. The next prime is 133220211003017. The reversal of 133220211002959 is 959200112022331.
It is a weak prime.
It is an emirp because it is prime and its reverse (959200112022331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133220211002959 - 25 = 133220211002927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133220211002939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610105501479 + 66610105501480.
It is an arithmetic number, because the mean of its divisors is an integer number (66610105501480).
Almost surely, 2133220211002959 is an apocalyptic number.
133220211002959 is a deficient number, since it is larger than the sum of its proper divisors (1).
133220211002959 is an equidigital number, since it uses as much as digits as its factorization.
133220211002959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 40.
The spelling of 133220211002959 in words is "one hundred thirty-three trillion, two hundred twenty billion, two hundred eleven million, two thousand, nine hundred fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •